Barbara David
Barbara and David can finish a piece of work in ^@10^@ and ^@20^@ days respectively. If this work is done by both of them on alternate days (starting with Barbara), how many days will it take for them to finish the work^@?^@


Answer:

^@ 13 ^@ days

Step by Step Explanation:
  1. 10 = rem
    m = 10
    n = 5
  2. Barbara takes ^@10^@ days to finish the work. So in ^@1^@ day, she finishes ^@\dfrac { 1 }{ 10 }^@ of the work.
  3. David takes ^@20^@ days to finish the work. So in ^@1^@ day, he finishes ^@\dfrac { 1 }{ 20 }^@ of the work.
  4. Since the work is done on alternate days, so the work done in two days ^@= \dfrac{ 1 }{ 10 } + \dfrac{ 1 } { 20 } = \dfrac{ 2 + 1 }{ 20 } = \dfrac{ 3 }{ 20 } ^@
  5. Multiply ^@ \dfrac{ 3 }{ 20 } ^@ by number such that it is less than or equal to ^@1.^@
    The work done in ^@ 12 ^@ days ^@ = 6 \times \dfrac{ 3 }{ 20 } = \dfrac { 9 }{ 10 } ^@
  6. Remaining work ^@ = 1 - \dfrac { 9 }{ 10 } = \dfrac { 1 }{ 10 } ^@
  7. Since, they work in alternate days, on ^@ 13^{th} ^@ day remaining work ^@ \dfrac { 1 }{ 10 } ^@ is done by Barbara.
  8. Thus, they will take ^@ 13 ^@ days to finish the work.

You can reuse this answer
Creative Commons License