A coin is tossed once. What is the probability of getting a head.
Answer:
^@ \dfrac { 1 } { 2 } ^@
- When a coin is tossed once, the possible outcomes are head and tail.
Let ^@ E ^@ be an event of getting a head.
Total number of possible outcomes = ^@2^@.
The favourable outcome is a head.
So, the number of favourable outcomes = ^@1^@
@^ \begin{aligned} \therefore P(\text{ getting a } head) = P(E) = \dfrac { \text{ Number of favourable outcomes } } { \text{ Total number of possible outcomes } } = \dfrac { 1 } { 2 } \end{aligned} @^